C basic mathematical operation

Question

1.00/5 (1 vote)

See more:

Write a program that reads there integers from the user(keyboard) namely, n, a and b. Your program sohuld print all positive numbers satisfying the following condition:

*The number smaller than n and the ratio of the number and sum of its positive divisors is equal to a/b.

You should print the number in ascending order and print their positive divisors on the sam eline as the numbers.

Example
If the user entered n: 10, a: 1, and b:2 then since only 6 satisfies the condition the output should be 6 and it positive divisors as follows :
6 1 2 3 6

(I am a first class engineering student. I do not want to miss the Basic. Homework, I have to deliver it by the end of the day tomorrow. :/ )

What I have tried:

Objective-C

<pre>int a,b,n;

int main()
{
	printf("please enter a number for n");
	scanf("%d",n);
	printf("please enter a number for a");
	scanf("%d",a);
	printf("please enter a number for b");
	scanf("%d",b);
	
	int i = 1;
	for(i = 1; i<n; i++)
	
	return 0;
}

int sumofdivisors(int a)
{
	int i;
	int sum = 0;
	for(i=1;i<=a;i++)
	{
		if(a%i==0)
		sum += i;
	}
	return sum;
}

Posted 19-Oct-17 2:58am

E.Açıkgöz

Updated 19-Oct-17 4:03am

v3

Add a Solution

Comments

ZurdoDev 19-Oct-17 9:08am

Then ask a question. It's rude and lazy to post your homework and not even ask a question.

E.Açıkgöz 19-Oct-17 9:12am

I do not do homework here directly. I tried a bit but I did not.

jeron1 19-Oct-17 10:51am

Can you accomplish this using paper and pencil?

2 solutions

Add a Solution

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

KarstenK · Answer 1 · 2017-10-19T03:52:00

You should write for every needed output a function which deliver it and than do the output.

You can define an array like this, but you also need to free the memory:

C++

int *arr = 0;// define pointer

int count = fillArrayFunc( arr, a, b, n );

for( int i = 0; i <count; i++ ) {
  int number = arr[i];//access
  printf("The number is: %d", number);
}
free( arr );//release the memory

//somewhere else do math and calc the stuff
int count fillArrayFunc( int *arr, int n, int a, int b) 
{
   arr = malloc( sizeof(int) * count );// alloc on input pointer

  return count;// needed for the output
}

You missed to ask earlier, so you have NOW the problem.

Richard MacCutchan · Answer 2 · 2017-10-19T03:47:00

Solution 1

The following code makes no sense. The first iteration of your loop will terminate your program.

C++

for(i = 1; i<n; i++)

return 0;

Posted 19-Oct-17 3:47am

Richard MacCutchan

Comments

KarstenK 20-Oct-17 2:33am

An array starts with 0. See it as offset from the starting point. Watch or read some tutorial to understand that BASIC concept of programming. You MUST understand that!!!

C basic mathematical operation

2 solutions

Solution 2

Solution 1

Add your solution here

Preview 0

C basic mathematical operation

2 solutions

Solution 2

Solution 1

Add your solution here

Preview 0

Existing Members

...or Join us